Thanks for asking! Weâ€™re glad to know the video was helpful, and are happy to extend your understanding to make sense of these two additional questions. Letâ€™s treat them one at a time.

First, if you havenâ€™t already, we strongly recommend practicing the *four* different approaches you need to know how to use to solve different related rates problems. Theyâ€™re all listed on our related rates page, and there are practice problems (with complete solutions, of course) for each type. Weâ€™ll be making use of two of these types for your problems, starting with the â€śGeometric Factâ€ť one:

(1) at what rate the area of the triangle formed by the ladder, wall, and ground is changing

Since the problem asks for the rate at which the *area* is changing, weâ€™re going to use â€śa Simple Geometric Factâ€ť (as explained on the related rates page). Specifically, the area of a triangle is

A = \frac{1}{2}xy

where weâ€™re using the same notation as in the video: x is the base of the triangle, and y is its height.

If we take the derivative with respect to time of both sides, we have

\frac{dA}{dt} = \frac{1}{2}\left[\dfrac{dx}{dt}y + x \dfrac{dy}{dt} \right]

I assume the problem gives you \dfrac{dx}{dt}, the rate at which the ladder moves away from the wall, and I also assume that you found the rate the ladder slides down the wall, \dfrac{dy}{dt}, earlier when you followed the video. (But if not, weâ€™re happy to help with that! Just let us know.) If you have all of those quantities, you should be set. (But if you have questions, please let us know where youâ€™re stuck and weâ€™ll do our best to help.)

(2) And at what rate the angle between the the ladder and the ground is changing.

Since this is asking about an angle, the approach we need (again from the Related Rates page) is â€śUsing a Trig Function.â€ť In fact, this very problem is there, the first in that subsection, â€śRelated Rates: Ladder slides, angle changes.â€ť I hope that will be enough to guide you in developing the solution to your problem, but again, if you need more assistance please just ask.

For now, thanks again for your compliment and questions â€“ and please feel free to submit more!